6(2x^2-4)+5x^2=1064

Solution for 6(2x^2-4)+5x^2=1064 equation:

6(2x^2-4)+5x^2=1064

We move all terms to the left:

6(2x^2-4)+5x^2-(1064)=0

We multiply parentheses

5x^2+12x^2-24-1064=0

We add all the numbers together, and all the variables

17x^2-1088=0

a = 17; b = 0; c = -1088;
Δ = b2-4ac
Δ = 02-4·17·(-1088)
Δ = 73984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{73984}=272$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-272}{2*17}=\frac{-272}{34}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+272}{2*17}=\frac{272}{34}
=8
$